Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

question 23 of 25 in cats, short hair is dominant over long hair. a cat…

Question

question 23 of 25

in cats, short hair is dominant over long hair. a cat with a heterozygous genotype for hair length is crossed with a cat with a homozygous recessive genotype.

what is the probability that an offspring will have the homozygous recessive genotype?

a. 0.50
b. 0.00
c. 0.75
d. 0.25

Explanation:

Response

<pre_analysis>
{
"quality": "clear",
"question_count": 1,
"skills_matched": [
"step_cot",
"multiple_choice_formatter",
"explain_then_answer",
"quick"
],
"needs_drawing": false,
"concepts_used": [
"Monohybrid Cross",
"Genotype",
"Dominance"
],
"new_concepts": [],
"current_concepts": [
"Monohybrid Cross",
"Genotype",
"Dominance",
"Mendelian Genetics"
]
}
</pre_analysis>

<reasoning>

Define alleles and parental genotypes

Let \(H\) represent the dominant allele for short hair, and \(h\) represent the recessive allele for long hair.

  • Heterozygous parent: \(Hh\)
  • Homozygous recessive parent: \(hh\)

Determine offspring genotypes using a Punnett square

Cross \(Hh \times hh\):

  • Gametes from heterozygous parent: \(H\), \(h\)
  • Gametes from homozygous recessive parent: \(h\)

The resulting offspring genotypes are:

  • \(Hh\) (heterozygous)
  • \(hh\) (homozygous recessive)

Calculate the probability of the homozygous recessive genotype

The ratio of offspring genotypes is:

  • \(50\%\) \(Hh\)
  • \(50\%\) \(hh\)

Therefore, the probability of an offspring having the homozygous recessive genotype (\(hh\)) is:
\[
P(hh) = 0.50
\]
</reasoning>

<answer>
<mcq-correct>(A) 0.50</mcq-correct>
<mcq-option>(B) 0.00</mcq-option>
<mcq-option>(C) 0.75</mcq-option>
<mcq-option>(D) 0.25</mcq-option>
</answer>

<post_analysis>
{
"subject": "Natural Science",
"question_type": "Multiple Choice",
"knowledge_point": [
"Natural Science",
"Biology",
"Mendelian Genetics"
]
}
</post_analysis>

Answer:

<pre_analysis>
{
"quality": "clear",
"question_count": 1,
"skills_matched": [
"step_cot",
"multiple_choice_formatter",
"explain_then_answer",
"quick"
],
"needs_drawing": false,
"concepts_used": [
"Monohybrid Cross",
"Genotype",
"Dominance"
],
"new_concepts": [],
"current_concepts": [
"Monohybrid Cross",
"Genotype",
"Dominance",
"Mendelian Genetics"
]
}
</pre_analysis>

<reasoning>

Define alleles and parental genotypes

Let \(H\) represent the dominant allele for short hair, and \(h\) represent the recessive allele for long hair.

  • Heterozygous parent: \(Hh\)
  • Homozygous recessive parent: \(hh\)

Determine offspring genotypes using a Punnett square

Cross \(Hh \times hh\):

  • Gametes from heterozygous parent: \(H\), \(h\)
  • Gametes from homozygous recessive parent: \(h\)

The resulting offspring genotypes are:

  • \(Hh\) (heterozygous)
  • \(hh\) (homozygous recessive)

Calculate the probability of the homozygous recessive genotype

The ratio of offspring genotypes is:

  • \(50\%\) \(Hh\)
  • \(50\%\) \(hh\)

Therefore, the probability of an offspring having the homozygous recessive genotype (\(hh\)) is:
\[
P(hh) = 0.50
\]
</reasoning>

<answer>
<mcq-correct>(A) 0.50</mcq-correct>
<mcq-option>(B) 0.00</mcq-option>
<mcq-option>(C) 0.75</mcq-option>
<mcq-option>(D) 0.25</mcq-option>
</answer>

<post_analysis>
{
"subject": "Natural Science",
"question_type": "Multiple Choice",
"knowledge_point": [
"Natural Science",
"Biology",
"Mendelian Genetics"
]
}
</post_analysis>