Question

question 23 of 25

in cats, short hair is dominant over long hair. a cat with a heterozygous genotype for hair length is crossed with a cat with a homozygous recessive genotype.

what is the probability that an offspring will have the homozygous recessive genotype?

a. 0.50
b. 0.00
c. 0.75
d. 0.25

Explanation:

Define alleles and parental genotypes

Let \(H\) represent the dominant allele for short hair, and \(h\) represent the recessive allele for long hair.

• Heterozygous parent: \(Hh\)
• Homozygous recessive parent: \(hh\)

Determine offspring genotypes using a Punnett square

Cross \(Hh \times hh\):

• Gametes from heterozygous parent: \(H\), \(h\)
• Gametes from homozygous recessive parent: \(h\)

The resulting offspring genotypes are:

• \(Hh\) (heterozygous)
• \(hh\) (homozygous recessive)

Calculate the probability of the homozygous recessive genotype

The ratio of offspring genotypes is:

• \(50\%\) \(Hh\)
• \(50\%\) \(hh\)

Therefore, the probability of an offspring having the homozygous recessive genotype (\(hh\)) is:

$$ P(hh) = 0.50 $$

Answer:

• (A) 0.50 (Correct answer)
• (B) 0.00
• (C) 0.75
• (D) 0.25