Question

yellowstone national park has 124 wolves living in it. the park covers 3472 square miles. what is the population density of wolves living in yellowstone?
a. \\(28\text{ wolves/mi}^2\\)
b. \\(0.0357\text{ wolves/mi}^2\\)
c. \\(82\text{ wolves/mi}^2\\)
d. \\(43\text{ wolves/mi}^2\\)

please select the best answer from the choices provided

Explanation:

🆕 New Concept Discovered: Population Density
How crowded a region is with organisms.

Step 1: Identify the formula for population density

Population density measures how many individuals of a population live in a specific unit of area.

$$ \text{Population Density} = \frac{\text{Number of Individuals}}{\text{Land Area}} $$

Step 2: Substitute the given values

From the problem, we have:

• Number of wolves = \(124\)
• Land area = \(3472\text{ mi}^2\)

$$ \text{Population Density} = \frac{124\text{ wolves}}{3472\text{ mi}^2} $$

Step 3: Calculate the density

Divide the numerator by the denominator:

$$ \frac{124}{3472} \approx 0.035714\text{ wolves/mi}^2 $$

Rounding to four decimal places gives \(0.0357\text{ wolves/mi}^2\).

Answer:

B (or b. 0.0357 wolves/mi²)