Question

windy weather mystery math
name three types of windy storms.
1.
2.
3.
round each decimal to the nearest hundredth. write the answer in the middle square then find the letter that corresponds to your answer in the key above. write the corresponding letter in the bottom square to uncover three types of windy weather. the first one is done for you.

Explanation:

Step1: Round 4.107 to the nearest hundredth

The digit in the thousandth place is 7. Since \(7\geq5\), we round up the hundredth place digit. So \(4.107\approx4.11\). Looking at the key, \(4.11\) corresponds to \(U\).

Step2: Round 1.562 to the nearest hundredth

The digit in the thousandth place is 2. Since \(2 < 5\), we leave the hundredth place digit as it is. So \(1.562\approx1.56\). Looking at the key, \(1.56\) corresponds to \(R\).

Step3: Round 1.559 to the nearest hundredth

The digit in the thousandth place is 9. Since \(9\geq5\), we round up the hundredth place digit. So \(1.559\approx1.56\) (because \(5 + 1=6\) in the hundredth place). Looking at the key, \(1.56\) corresponds to \(R\).

Step4: Round 2.843 to the nearest hundredth

The digit in the thousandth place is 3. Since \(3 < 5\), we leave the hundredth place digit as it is. So \(2.843\approx2.84\). Looking at the key, \(2.84\) corresponds to \(I\).

Step5: Round 9.891 to the nearest hundredth

The digit in the thousandth place is 1. Since \(1 < 5\), we leave the hundredth place digit as it is. So \(9.891\approx9.89\). Looking at the key, \(9.89\) corresponds to \(C\).

Step6: Round 5.548 to the nearest hundredth

The digit in the thousandth place is 8. Since \(8\geq5\), we round up the hundredth place digit. So \(5.548\approx5.55\). Looking at the key, \(5.55\) corresponds to \(A\).

Step7: Round 3.305 to the nearest hundredth

The digit in the thousandth place is 5. Since \(5\geq5\), we round up the hundredth place digit. So \(3.305\approx3.31\). Looking at the key, \(3.31\) corresponds to \(N\).

Step8: Round 7.776 to the nearest hundredth

The digit in the thousandth place is 6. Since \(6\geq5\), we round up the hundredth place digit. So \(7.776\approx7.78\). Looking at the key, \(7.78\) corresponds to \(E\).

Step9: Round 9.559 to the nearest hundredth

The digit in the thousandth place is 9. Since \(9\geq5\), we round up the hundredth place digit. So \(9.559\approx9.56\). Looking at the key, \(9.56\) corresponds to \(B\).

Step10: Round 3.154 to the nearest hundredth

The digit in the thousandth place is 4. Since \(4 < 5\), we leave the hundredth place digit as it is. So \(3.154\approx3.15\). Looking at the key, \(3.15\) corresponds to \(L\).

Step11: Round 2.837 to the nearest hundredth

The digit in the thousandth place is 7. Since \(7\geq5\), we round up the hundredth place digit. So \(2.837\approx2.84\). Looking at the key, \(2.84\) corresponds to \(I\).

Step12: Round 1.752 to the nearest hundredth

The digit in the thousandth place is 2. Since \(2 < 5\), we leave the hundredth place digit as it is. So \(1.752\approx1.75\). Looking at the key, \(1.75\) corresponds to \(Z\).

Step13: Round 1.746 to the nearest hundredth

The digit in the thousandth place is 6. Since \(6\geq5\), we round up the hundredth place digit. So \(1.746\approx1.75\). Looking at the key, \(1.75\) corresponds to \(Z\).

Step14: Round 5.553 to the nearest hundredth

The digit in the thousandth place is 3. Since \(3 < 5\), we leave the hundredth place digit as it is. So \(5.553\approx5.55\). Looking at the key, \(5.55\) corresponds to \(A\).

Step15: Round 1.564 to the nearest hundredth

The digit in the thousandth place is 4. Since \(4 < 5\), we leave the hundredth place digit as it is. So \(1.564\approx1.56\). Looking at the key, \(1.56\) corresponds to \(R\).

Step16: Round 2.625 to the nearest hundredth

The digit in the thousandth place is 5. Since \(5\geq5\), we round up the hundredth place digit. So \(2.625\approx2.63\). Looking at the key, \(2.63\) corresponds to \(D\).

Step17: Round 1.422 to the nearest hundredth

The digit in the thousandth place is 2. Since \(2 < 5\), we leave the hundredth place digit as it is. So \(1.422\approx1.42\). Looking at the key, \(1.42\) corresponds to \(T\).

Step18: Round 8.770 to the nearest hundredth

The digit in the thousandth place is 0. Since \(0 < 5\), we leave the hundredth place digit as it is. So \(8.770\approx8.77\). Looking at the key, \(8.77\) corresponds to \(O\).

Step19: Round 1.557 to the nearest hundredth

The digit in the thousandth place is 7. Since \(7\geq5\), we round up the hundredth place digit. So \(1.557\approx1.56\). Looking at the key, \(1.56\) corresponds to \(R\).

Step20: Round 3.314 to the nearest hundredth

The digit in the thousandth place is 4. Since \(4 < 5\), we leave the hundredth place digit as it is. So \(3.314\approx3.31\). Looking at the key, \(3.31\) corresponds to \(N\).

Step21: Round 5.546 to the nearest hundredth

The digit in the thousandth place is 6. Since \(6\geq5\), we round up the hundredth place digit. So \(5.546\approx5.55\). Looking at the key, \(5.55\) corresponds to \(A\).

Step22: Round 2.631 to the nearest hundredth

The digit in the thousandth place is 1. Since \(1 < 5\), we leave the hundredth place digit as it is. So \(2.631\approx2.63\). Looking at the key, \(2.63\) corresponds to \(D\).

Step23: Round 8.765 to the nearest hundredth

The digit in the thousandth place is 5. Since \(5\geq5\), we round up the hundredth place digit. So \(8.765\approx8.77\). Looking at the key, \(8.77\) corresponds to \(O\).

After filling all the letters, we can find the three types of windy weather. Assuming the first one (with \(h\) as part of it) is a typo - like if we consider the full words formed by the letters:
- One type could be "hurricane" (using letters from the first set of decimals - if we assume some order of combination, for example, if we take the letters \(H\) (from \(6.32\)), \(U\), \(R\), \(R\), \(I\), \(C\), \(A\), \(N\), \(E\)).
- Another could be "blizzard" (using \(B\), \(L\), \(I\), \(Z\), \(Z\), \(A\), \(R\), \(D\)).
- The third could be "tornado" (\(T\), \(O\), \(R\), \(N\), \(A\), \(D\), \(O\)).

Answer:

1. Hurricane
2. Blizzard
3. Tornado