1. what is the % of glucose and sodium outside the cell?
2. what is the % of glucose and sodium inside the cell?
3. what is the % of water outside the cell?
4. what is the % of water inside the cell?
5. will osmosis occur?
6. the cell is in what type of solution (hypertonic, hypotonic, isotonic)?
(diagram text: 20% glucose, 15% sodium (outside cell); 35% glucose (inside cell))

Question

Accepted Answer

### 1. What is the % of glucose and sodium outside the cell?
# Brief Explanations:
From the diagram, the outside (extracellular) has 20% Glucose and 15% Sodium.
# Answer:
Glucose: 20%, Sodium: 15%

### 2. What is the % of glucose and sodium inside the cell?
# Brief Explanations:
The cell (intracellular) has 35% Glucose. There's no sodium data given, so assume sodium inside is 0% (or not provided, but glucose is 35%).
# Answer:
Glucose: 35%, Sodium: 0% (or not provided)

### 3. What is the % of water outside the cell?
# Explanation:
## Step1: Total outside is 100%. Subtract glucose and sodium.
Total outside components: Glucose (20%) + Sodium (15%) + Water. So Water % = $100 - 20 - 15$.
## Step2: Calculate.
$100 - 20 - 15 = 65$.
# Answer:
65%

### 4. What is the % of water inside the cell?
# Explanation:
## Step1: Total inside is 100%. Subtract glucose (sodium is 0% here).
Water % = $100 - 35$.
## Step2: Calculate.
$100 - 35 = 65$? Wait, no—wait, inside has 35% glucose, so water is $100 - 35 = 65$? Wait, no, wait: Wait, outside has 20% glucose, 15% sodium, so water 65%. Inside has 35% glucose, so water is $100 - 35 = 65$? Wait, no, maybe I made a mistake. Wait, no—wait, the inside cell: glucose is 35%, so water is 100 - 35 = 65%? Wait, but let's check. Total inside: glucose (35%) + water + sodium (0%) = 100. So water = 100 - 35 = 65%.
# Answer:
65% (Wait, but wait, maybe I messed up. Wait, outside: 20 +15=35, so water 65. Inside: 35 glucose, so water 65? Then osmosis? Wait, no, maybe the sodium inside is different? Wait, the diagram only shows 35% glucose inside. So assuming sodium inside is 0, then water inside is 65%.

### 5. Will osmosis occur?
# Brief Explanations:
Osmosis occurs if water concentration (or solute concentration) differs. Outside water: 65%, inside water: 65%? Wait, no—wait, outside solute (glucose + sodium) is 20 +15=35%, inside solute (glucose) is 35%. So solute concentration is same? Wait, no: outside solute is 35% (20+15), inside solute is 35% (35). So water concentration is same (65% outside, 65% inside). Wait, but maybe sodium inside is not 0? Wait, the diagram doesn't show sodium inside. If we assume sodium inside is different, but the given data: outside has 20% glucose, 15% sodium. Inside has 35% glucose. So solute outside: 35%, solute inside: 35% (glucose only, sodium 0? Then solute inside is 35, outside 35. So water is same. So no osmosis? Wait, but maybe I misread. Wait, the outside is 20% glucose, 15% sodium. Inside is 35% glucose. So total solute outside: 35%, inside: 35% (glucose). So water concentration is same (65% each). So osmosis won't occur? Wait, but maybe sodium inside is present? The diagram doesn't show. So based on given data, solute outside (35%) and inside (35%) are equal. So water potential is same, no osmosis.
# Answer:
No (if solute concentrations are equal; but wait, maybe sodium inside is 0, so solute inside is 35, outside 35. So yes, equal. So no osmosis.)

### 6. The cell is in what type of solution (hypertonic, hypotonic, isotonic)?
# Brief Explanations:
Isotonic solution has equal solute concentration. Outside solute: 20% glucose +15% sodium =35%. Inside solute: 35% glucose (assuming sodium inside is 0, but total solute is 35%). So solute concentrations are equal. So isotonic.
# Answer:
Isotonic

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QUESTION IMAGE

Question

Explanation:

1. What is the % of glucose and sodium outside the cell?

Step1: Total outside is 100%. Subtract glucose and sodium.

Step2: Calculate.

Answer:

2. What is the % of glucose and sodium inside the cell?