Question

1. use the following punnett squares you just created to answer the following question below in a cer format.

which possible cross will result in puppies that are not likely going to be deaf ?
claim
evidence
reasoning

Explanation:

To answer this, we assume a genetic context (common with deafness in puppies, e.g., white coat/deafness link in dogs, recessive traits). A cross with parents having dominant alleles for non - deafness (or no recessive deafness alleles) would work. For example, if deafness is recessive (let's say allele \( d \) for deaf, \( D \) for non - deaf), a cross like \( DD\times DD \) or \( DD\times Dd \) would have high non - deaf probability. The claim would state the cross, evidence from Punnett square (e.g., all or most puppies have \( D \) alleles), and reasoning about dominant/recessive inheritance. Since the Punnett squares aren't shown, we base on typical genetics: a cross between two dogs homozygous dominant for the non - deaf trait (or with very low recessive allele presence) results in puppies not likely deaf. For a CER:

• Claim: A cross between two dogs without the recessive allele for deafness (e.g., \( DD\times DD \)) results in puppies not likely to be deaf.
• Evidence: From the Punnett square (not shown here, but in general), all offspring would inherit at least one dominant allele, so no (or very few) recessive homozygotes (deaf) are produced.
• Reasoning: Deafness (if recessive) requires two recessive alleles (\( dd \)). If parents don't have the recessive allele, offspring can't get two \( d \) alleles, so they won't be deaf.

Answer:

Claim:

A cross between two dogs that do not carry the recessive allele for deafness (e.g., a cross of two homozygous dominant dogs for the non - deaf trait) will result in puppies that are NOT likely going to be deaf.

Evidence:

(Assuming the Punnett square for such a cross) All of the possible offspring genotypes from this cross will contain at least one dominant allele for the non - deaf trait, meaning there will be no (or a very low number of) genotypes that result in deafness.

Reasoning:

If deafness is a recessive trait (requiring two recessive alleles to be expressed), offspring need to inherit two recessive alleles (one from each parent) to be deaf. When parents do not carry the recessive allele for deafness, they cannot pass on the recessive allele to their offspring. Thus, the offspring will not have the genotype required for deafness, making them not likely to be deaf.