Question

two plants are heterozygous for seed shape and have round seeds. if the two plants are crossed, what is the probability that the offspring will have wrinkled seeds? 25 percent 50 percent 75 percent 100 percent

Explanation:

Step1: Determine the genotypes

Let \( R \) represent the dominant allele (round seeds) and \( r \) represent the recessive allele (wrinkled seeds). The heterozygous plants have the genotype \( Rr \).

Step2: Set up the Punnett square

When crossing \( Rr\times Rr \), the possible gametes from each parent are \( R \) and \( r \). The Punnett square is:

	\( R \)	\( r \)
\( r \)	\( Rr \)	\( rr \)

Step3: Analyze the results

The genotypes of the offspring are \( RR:Rr:rr = 1:2:1 \). The \( rr \) genotype corresponds to wrinkled seeds. So the probability of \( rr \) is \( \frac{1}{4}=0.25 = 25\% \)

Answer:

25 percent