Question

two plants are heterozygous for seed shape and have round seeds. if the two plants are crossed, what is the probability that the offspring will have wrinkled seeds?
25 percent
50 percent
75 percent
100 percent

Explanation:

Step1: Determine the genotypes

Let \( R \) represent the allele for round seeds (dominant) and \( r \) represent the allele for wrinkled seeds (recessive). The two heterozygous plants have the genotype \( Rr \).

Step2: Set up the Punnett square

When crossing \( Rr\times Rr \), the possible gametes from each parent are \( R \) and \( r \). The Punnett square is:

	\( R \)	\( r \)
\( r \)	\( Rr \)	\( rr \)

Step3: Calculate the probability

The genotypes of the offspring are \( RR:Rr:rr = 1:2:1 \). The \( rr \) genotype corresponds to wrinkled seeds. So the probability of \( rr \) is \( \frac{1}{4}= 25\% \)

Answer:

25 percent