Question

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a pea plant with genotype pp (purple flowers) mates with a plant with the genotype pp (white flowers). the dominant allele p codes for purple flowers. the possibility that the offspring will have purple flowers is . if an offspring from this cross mates with a pp, the possibility of homozygous dominant genotype for the flowers will be .

Explanation:

Step1: Analyze the cross

The cross is between Pp (purple) and pp (white). Using a Punnett square, the possible genotypes of the offspring are Pp and pp.

Step2: Determine the probability of purple flowers

Purple flowers are determined by the presence of the dominant allele P. The genotypes Pp (heterozygous) will show purple flowers. From the Punnett square, out of 2 possible genotypes (Pp and pp), 1 is Pp. So the probability is $\frac{1}{2}$ or 50%.

Step3: Analyze the second part (if an offspring from this cross mates with a pp)

If an offspring (which can be Pp or pp) mates with pp. If the offspring is Pp (probability 50% from the first cross), then using Punnett square for Pp x pp: genotypes are Pp and pp (50% chance of Pp). If the offspring is pp (probability 50% from the first cross), then pp x pp gives all pp. So overall probability: $(0.5\times0.5)+(0.5\times0)=0.25$ or 25%.

Answer:

The probability that the offspring will have purple flowers is 50%. If an offspring from this cross mates with a pp, the probability of homozygous dominant genotype for the flowers will be 25%.