Question

section ii: monohybrid crosses

1. round seeds (r) are dominant to wrinkled (r) seeds. cross a homozygous dominant seed with a heterozygote.

parents = ____ x ____
image of a punnett square
genotype: ____% rr __% rr ____% rr
phenotype: ____% round ____% wrinkled

Explanation:

Step1: Identify Parent Genotypes

Homozygous dominant for round seeds is \( RR \), heterozygous is \( Rr \). So parents: \( RR \times Rr \).

Step2: Set Up Punnett Square

	\( R \)	\( R \)
\( r \)	\( Rr \)	\( Rr \)

Step3: Calculate Genotype Percentages

• \( RR \): 2 out of 4 = 50%
• \( Rr \): 2 out of 4 = 50%
• \( rr \): 0 out of 4 = 0%

Step4: Calculate Phenotype Percentages

• Round (\( RR, Rr \)): 4 out of 4 = 100%
• Wrinkled (\( rr \)): 0 out of 4 = 0%

Answer:

Parents: \( RR \times Rr \)
Genotype: 50% \( RR \), 50% \( Rr \), 0% \( rr \)
Phenotype: 100% round, 0% wrinkled