Question

a scientist is studying fruit fly wings. straight wings are dominant, and curly wings are recessive. which statement correctly describes the f₁ generation if a straight - winged parent is crossed with a curly - winged parent and if both parents are true breeding?
○ the offspring will have two genes for straight wings.
○ the offspring will produce only gametes that have genes for curly wings.
○ the offspring will have one allele for straight wings and one allele for curly wings.
○ the offspring will have only one kind of allele for the gene that determines wing type.

Explanation:

Let's assume the allele for straight wings is \(S\) (dominant) and for curly wings is \(s\) (recessive). A true - breeding straight - winged parent has the genotype \(SS\), and a true - breeding curly - winged parent has the genotype \(ss\). When they are crossed (\(SS\times ss\)):

• Using the Punnett square method, the gametes from the \(SS\) parent are all \(S\), and the gametes from the \(ss\) parent are all \(s\).
• The offspring will have the genotype \(Ss\). This means each offspring has one allele for straight wings (\(S\)) and one allele for curly wings (\(s\)).

Answer:

The offspring will have one allele for straight wings and one allele for curly wings.