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rryy x rryy (round and yellow are dominant, green and wrinkly are reces…

Question

rryy x rryy (round and yellow are dominant, green and wrinkly are recessive) considering the p1 above, what are the chances that the f1 generation will have green, wrinkly seeds? 1/32 1/2 1/8 1/16

Explanation:

Step1: Analyze the inheritance of each trait separately

For seed color: \(Yy\times Yy\). The probability of getting \(yy\) (green) is \(\frac{1}{4}\) (using Punnett square: \(YY:Yy:yy = 1:2:1\)).
For seed shape: \(Rr\times Rr\). The probability of getting \(rr\) (wrinkled) is \(\frac{1}{4}\) (using Punnett square: \(RR:Rr:rr=1:2:1\)).

Step2: Use the multiplication rule for independent events

Since the inheritance of seed - color and seed - shape are independent events (Mendel's law of independent assortment), the probability of getting green and wrinkled seeds (\(yyrr\)) is the product of the probabilities of getting \(yy\) and \(rr\).
\(P(yyrr)=P(yy)\times P(rr)\)
Substitute \(P(yy)=\frac{1}{4}\) and \(P(rr)=\frac{1}{4}\) into the formula: \(P(yyrr)=\frac{1}{4}\times\frac{1}{4}=\frac{1}{16}\)

Answer:

\(\frac{1}{16}\)