Question

refer to the following information on the genetic code. use this information to determine how many amino acids are coded for by the mrna sequence augcgcagucgguag. the genetic code

Explanation:

Step1: Divide mRNA into codons

The mRNA sequence is AUGCGCAGUCGGUA G. Divide it into triplets (codons): AUG - CGC - AGU - CGG - UAG.

Step2: Identify stop codon

UAG is a stop codon. Stop codons do not code for an amino acid.

Step3: Count coding codons

AUG codes for Methionine, CGC codes for Arginine, AGU codes for Serine, CGG codes for Arginine.

Answer:

4