Question

b. in rabbits, the allele for black coat (b) is dominant over the allele for a brown coat (b). cross a female rabbit that is homozygous dominant for black coat with a heterozygous male rabbit. then, answer the questions that follow: 1. how many possible genotypes are there among the offspring? 2. how many possible phenotypes are there among the offspring? 3. what percentage of the offspring are black - coated? 4. what percentage of the offspring are brown - coated? 5. what color is the male parent?

Explanation:

Step1: Determine the genotypes of the parents

The female rabbit is homozygous dominant for black coat, so its genotype is \( BB \). The male rabbit is heterozygous, so its genotype is \( Bb \).

Step2: Set up the Punnett square

The female can only contribute \( B \) alleles. The male can contribute \( B \) or \( b \) alleles.

	\( B \)	\( b \)
\( B \)	\( BB \)	\( Bb \)

Step3: Analyze genotypes

The genotypes of the offspring are \( BB \) and \( Bb \). So there are \( 2 \) possible genotypes.

Step4: Analyze phenotypes

Since \( B \) is dominant over \( b \), both \( BB \) and \( Bb \) result in black - coat phenotype. So there is \( 1 \) possible phenotype.

Step5: Calculate percentage of black - coated offspring

Out of \( 4 \) squares in the Punnett square, \( 4 \) have genotypes (\( BB \) or \( Bb \)) that result in black coat. The percentage is \(\frac{4}{4}\times100\% = 100\%\).

Step6: Calculate percentage of brown - coated offspring

Since there are no \( bb \) genotypes (which would result in brown coat), the percentage is \( 0\%\).

Step7: Determine male parent's color

The male parent has genotype \( Bb \). Since \( B \) (black) is dominant, the male parent is black - coated.

Answer:

1. \( 2 \)
2. \( 1 \)
3. \( 100\%\)
4. \( 0\%\)
5. Black