Question

question 5 (2 points)
a cell with a k⁺¹ concentration of 0.3 eq/l is placed into a solution with a
k⁺¹ concentration of 0.2 eq/l. it is assumed that the k⁺¹ can pass through the cell
membrane (the k⁺¹ transport protein is open).
answer the following true or false questions.
1 k⁺¹ will diffuse through the membrane down its concentration gradient due
to kinetic theory
2 movement of a solute through the membrane is called dialysis
3 k⁺¹ will move out of the cell
a. true b. false

Explanation:

For Question 1:

Kinetic Theory explains that particles move randomly and diffuse from high to low concentration. The cell has 0.3 eq/L \( K^{+1} \), solution has 0.2 eq/L, so \( K^{+1} \) diffuses down the gradient (high to low) due to kinetic motion. So this is true (A).

For Question 2:

Dialysis is the movement of solutes across a semi - permeable membrane (like in this case, the cell membrane is semi - permeable and \( K^{+1} \) is a solute moving through). So the statement is true (A).

For Question 3:

The cell has a higher \( K^{+1} \) concentration (0.3 eq/L) than the solution (0.2 eq/L). Diffusion is from high to low concentration, so \( K^{+1} \) will move out of the cell (from cell to solution) to equalize concentrations. So this is true (A).

Answer:

1. A. true
2. A. true
3. A. true