practicing punnett squares:
a plant species has two alleles for leaf shape:
curly (g) and flat (g)
create a punnett square for homozygous recessive (gg) and a heterozygous (gg) parents.
what is the likelihood for phenotype of curly leaf shape?
in mussels, there are two alleles for coloring:
brown coloring (b) and blue coloring (b)
create a punnett square for a homozygous dominant (bb) and a homozygous recessive (bb) parent.
what is the likelihood for a phenotype of blue coloring?
in sheep, there are two alleles for belly fur:
belly fur (a) and no belly fur (a)
create a punnett square for a mother with the genotype aa and a father with a genotype aa
what is the likelihood for a genotype of aa?
a punnett square below shows the genotypes of offspring for the hair length trait in cats.
short hair (h) and long hair (h)
what is the likelihood for a phenotype of short hair?
what is the likelihood that any offspring will have a dominant allele?

Question

Accepted Answer

### First Sub - Question (Plant Leaf Shape)
# Explanation:
## Step1: Determine Parent Genotypes
The homozygous recessive parent has genotype $ gg $, so it can only contribute $ g $ alleles. The heterozygous parent has genotype $ Gg $, so it can contribute $ G $ or $ g $ alleles.
## Step2: Create Punnett Square
| | $ g $ | $ g $ |
| --- | --- | --- |
| $ G $ | $ Gg $ | $ Gg $ |
| $ g $ | $ gg $ | $ gg $ |
## Step3: Analyze Phenotype
The curly leaf shape is dominant (associated with $ G $). The genotypes $ Gg $ show the curly phenotype. From the Punnett square, there are 2 out of 4 (or $ \frac{1}{2} $ or 50%) of the offspring with $ Gg $ genotype.
# Answer: 50% (or $ \frac{1}{2} $)

### Second Sub - Question (Mussel Coloring)
# Explanation:
## Step1: Determine Parent Genotypes
The homozygous dominant parent has genotype $ BB $, so it can only contribute $ B $ alleles. The homozygous recessive parent has genotype $ bb $, so it can only contribute $ b $ alleles.
## Step2: Create Punnett Square
| | $ b $ | $ b $ |
| --- | --- | --- |
| $ B $ | $ Bb $ | $ Bb $ |
| $ B $ | $ Bb $ | $ Bb $ |
## Step3: Analyze Phenotype
The blue coloring is recessive (associated with $ bb $). All offspring have $ Bb $ genotype, so the phenotype of blue coloring ( $ bb $) has a likelihood of 0.
# Answer: 0%

### Third Sub - Question (Sheep Belly Fur)
# Explanation:
## Step1: Determine Parent Genotypes
Both parents have genotype $ Aa $, so each can contribute $ A $ or $ a $ alleles.
## Step2: Create Punnett Square
| | $ A $ | $ a $ |
| --- | --- | --- |
| $ A $ | $ AA $ | $ Aa $ |
| $ a $ | $ Aa $ | $ aa $ |
## Step3: Analyze Genotype Likelihood
The genotype $ AA $ appears 1 out of 4 times in the Punnett square. So the likelihood is $ \frac{1}{4} $ or 25%.
# Answer: 25% (or $ \frac{1}{4} $)

### Fourth Sub - Question (Cat Hair Length - Short Hair Likelihood)
# Explanation:
## Step1: Analyze Genotypes in Punnett Square
The Punnett square has all $ hh $ genotypes. Short hair is associated with the dominant allele $ H $. Since all genotypes are $ hh $ (recessive for long hair), there are no genotypes with $ H $ (required for short hair phenotype).
## Step2: Determine Likelihood
The likelihood of short hair (which requires at least one $ H $) is 0.
# Answer: 0%

### Fifth Sub - Question (Cat Hair Length - Dominant Allele Likelihood)
# Explanation:
## Step1: Analyze Genotypes in Punnett Square
All genotypes in the Punnett square are $ hh $, which has no dominant allele ( $ H $ is the dominant allele here).
## Step2: Determine Likelihood
The number of offspring with a dominant allele ( $ H $) is 0 out of 4. So the likelihood is 0.
# Answer: 0%

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QUESTION IMAGE

Question

Explanation:

First Sub - Question (Plant Leaf Shape)

Step1: Determine Parent Genotypes

Step2: Create Punnett Square

Step3: Analyze Phenotype

Step1: Determine Parent Genotypes

Step2: Create Punnett Square

Step3: Analyze Phenotype

Step1: Determine Parent Genotypes

Step2: Create Punnett Square

Step3: Analyze Genotype Likelihood

Answer:

Second Sub - Question (Mussel Coloring)