Question

the planet jupiter has a mass of 1.9 10^{27} kg and a radius of 72,000 km. the earth, meanwhile, has a mass of 6.0 10^{24} kg and a radius of 6,400 km.

• part (a)

what is the volume v of jupiter in m^{3}?
v = 1.56 * 10^{24}
v = 1560 * 10^{21} m^{3}

• part (b)

calculate the density \
ho of jupiter in kg/m^{3}.
\
ho = 1.22 * 10^{3}
\
ho = 1220 kg/m^{3}

• part (c)

what is the volume v of earth in m^{3}?
v = 1.10 * 10^{21}
v = 1.100 * 10^{21} m^{3}

• part (d)

calculate the density \
ho of earth in kg/m^{3}.
\
ho = kg/m^{3}
hints: deduction per hint. hints remaining: 1
feedback: deduction per feedback

Explanation:

Step1: Recall the formula for density

Density formula is \(
ho=\frac{m}{V}\), where \(m\) is mass and \(V\) is volume.

Step2: Identify the mass and volume of Earth

Given \(m = 6.0\times10^{24}\text{ kg}\) and \(V=1.10\times 10^{21}\text{ m}^3\)

Step3: Calculate the density

Substitute values into formula: \(
ho=\frac{6.0\times 10^{24}}{1.10\times 10^{21}}\)

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Answer:

\(5.45\times 10^{3}\text{ kg/m}^3\)