Question

in a physics experiment, the accompanying table provides the mass (in kilograms), acceleration (in meters/second²), and the material of 10 objects. calculate the force (in newtons) applied to each cell of the final column using the formula force = mass × acceleration.
click the icon to view the object data.
calculate the force for each object.
(type integers or decimals. do not round.)

Explanation:

Step1: Calculate force for object 1

Using formula \(F = m\times a\), for object 1: \(m = 3\), \(a=0.6\). So \(F=3\times0.6 = 1.8\)

Step2: Calculate force for object 2

For object 2: \(m = 6\), \(a = 1.2\). So \(F=6\times1.2=7.2\)

Step3: Calculate force for object 3

For object 3: \(m = 9\), \(a = 1.8\). So \(F=9\times1.8 = 16.2\)

Step4: Calculate force for object 4

For object 4: \(m = 12\), \(a = 2.4\). So \(F=12\times2.4=28.8\)

Step5: Calculate force for object 5

For object 5: \(m = 15\), \(a = 3\). So \(F=15\times3=45\)

Step6: Calculate force for object 6

For object 6: \(m = 18\), \(a = 3.6\). So \(F=18\times3.6 = 64.8\)

Step7: Calculate force for object 7

For object 7: \(m = 21\), \(a = 4.2\). So \(F=21\times4.2=88.2\)

Step8: Calculate force for object 8

For object 8: \(m = 24\), \(a = 4.8\). So \(F=24\times4.8 = 115.2\)

Step9: Calculate force for object 9

For object 9: \(m = 27\), \(a = 5.4\). So \(F=27\times5.4=145.8\)

Step10: Calculate force for object 10

For object 10: \(m = 30\), \(a = 6\). So \(F=30\times6=180\)

Answer:

object	force
2	\(7.2\)
3	\(16.2\)
4	\(28.8\)
5	\(45\)
6	\(64.8\)
7	\(88.2\)
8	\(115.2\)
9	\(145.8\)
10	\(180\)