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Question
in physics class, carrie learns that a force, f, is equal to the mass of an object, m, times its acceleration, a. she writes the equation f=ma. using this formula, what is the acceleration of an object with f=7.92 newtons and m=3.6 kilograms? express your answer to the nearest tenth. note: the unit for force (the newton) is measured in \\(\frac{kg\cdot m}{s^2}\\). \\(\circ\\) \\(0.5\frac{m}{s^2}\\) \\(\circ\\) \\(1.8\frac{m}{s^2}\\) \\(\circ\\) \\(2.2\frac{m}{s^2}\\) \\(\circ\\) \\(4.9\frac{m}{s^2}\\)
Step1: Rearrange the formula for acceleration
We know that \( F = ma \). To solve for \( a \), we divide both sides of the equation by \( m \). So, \( a=\frac{F}{m} \).
Step2: Substitute the given values
We are given that \( F = 7.92 \) newtons and \( m = 3.6 \) kilograms. Substitute these values into the formula for \( a \): \( a=\frac{7.92}{3.6} \).
Step3: Calculate the value of \( a \)
\( \frac{7.92}{3.6}=2.2 \). So the acceleration \( a = 2.2\frac{m}{s^{2}} \) (since the units for force are \( \frac{kg\cdot m}{s^{2}} \) and mass is in kg, when we divide \( \frac{kg\cdot m}{s^{2}} \) by kg, we get \( \frac{m}{s^{2}} \)).
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C. \( 2.2\frac{m}{s^{2}} \) (assuming the options are labeled with C for the \( 2.2\frac{m}{s^{2}} \) option, if the original options had labels like A, B, C, D with C being \( 2.2\frac{m}{s^{2}} \))