Question

parents that are heterozygous for having freckles (dominant) are crossed. which correctly describes their offspring?
twenty-five percent have freckles.
twenty-five percent are ff.
seventy-five percent have freckles.
seventy-five percent are ff.

Explanation:

Step1: Define Genotypes

Let \( F \) be dominant (freckles), \( f \) recessive (no freckles). Heterozygous parents: \( Ff \times Ff \).

Step2: Punnett Square

	\( F \)	\( f \)
\( f \)	\( Ff \)	\( ff \)

Step3: Analyze Offspring

• Genotypes: \( FF \) (25%), \( Ff \) (50%), \( ff \) (25%).
• Phenotypes: \( FF \) and \( Ff \) have freckles (75%), \( ff \) does not (25%).

Answer:

Seventy - five percent have freckles.