Question

3 multiple choice 20 points one parent is heterozygous for a certain trait (dd). the other parent is homozygous dominant (dd) for that trait. what is the percent chance that an offspring from this cross will be heterozygous? 0% 25% 50% 75%

Explanation:

Step1: Set up the Punnett - square

The possible gametes from the heterozygous parent (Dd) are D and d. The possible gametes from the homozygous - dominant parent (DD) are all D.

Step2: Fill in the Punnett - square

	D	D
d	Dd	Dd

Step3: Calculate the probability

There are 4 possible genotypes for the offspring: 2 DD and 2 Dd. The probability of getting a heterozygous (Dd) offspring is $\frac{2}{4}=0.5$ or 50%.

Answer:

50%