Question

homework - possible points 11.11 the ab blood group in humans is controlled by a gene with two alleles, a and b, which are codominant. what would be the expected outcome of a cross between a mother with genotype ab and a father with genotype bb? there is a 100% chance the offspring will have the bb blood group there is a 100% chance the offspring will have the ab blood group there is a 50% chance the offspring will have the aa blood group and a 50% chance the offspring will have the bb blood group there is a 50% chance the offspring will have the ab blood group and a 50% chance the offspring will have the bb blood group

Explanation:

When crossing a mother with genotype \(AB\) (gametes \(A\) and \(B\)) and a father with genotype \(BB\) (gametes \(B\) and \(B\)), we use Punnett - square analysis. The possible combinations are \(AB\) (from \(A\) (mother) and \(B\) (father)) and \(BB\) (from \(B\) (mother) and \(B\) (father)). Each combination has an equal probability.

Answer:

There is a 50% chance the offspring will have the AB blood group and a 50% chance the offspring will have the BB blood group.