Question

homework - non-mendelian inheritance patterns

huntersyndrome is a serious sex - linked recessive disorder that leads to neurological problems and developmental delays the gene that controls this trait is located on the x chromosome if two parents with the genotypes shown in this punnett square have children, what is the expected phenotypic outcome?

there is a 100% chance that their sons will have the disorder, and a 50% chance that their daughters will have the disorder

there is a 50% chance that their sons will have the disorder, and a 50% chance that their daughters will have the disorder

there is a 100% chance that their sons will have the disorder, and 0% chance that their daughters will have the disorder

there is a 50% chance that their sons will have the disorder, and a 0% chance that their daughters will have the disorder

Explanation:

Step1: Analyze daughters' genotypes

The possible genotypes for daughters are \(X^{H}X^{H}\) and \(X^{H}X^{h}\). Since Hunter syndrome is recessive (\(X^{h}\)), daughters need two \(X^{h}\) alleles to show the disorder. So daughters have 0% chance.

Step2: Analyze sons' genotypes

The possible genotypes for sons are \(X^{H}Y\) and \(X^{h}Y\). Sons get one X - linked allele. Half of sons (\(X^{h}Y\)) will have the disorder.

Answer:

There is a 50% chance that their sons will have the disorder, and a 0% chance that their daughters will have the disorder.