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homework - complete dominance inheritance pattern the gene for black fu…

Question

homework - complete dominance inheritance pattern
the gene for black fur (b) is dominant over the gene for white fur (b) in mice. a homozygous dominant female and a heterozygous male produce 200 offspring during their lifetime. approximately how many offspring would be expected to be homozygous dominant?
25
50
100
200

Explanation:

Step1: Determine the genotypes of parents

The female is homozygous dominant (\(BB\)), and the male is heterozygous (\(Bb\)).

Step2: Do the Punnett square

Gametes of female (\(B\))Gametes of male (\(B\))Gametes of male (\(b\))

The probability of getting \(BB\) (homozygous dominant) is \(\frac{1}{2}\).

Step3: Calculate the number of homozygous dominant offspring

If there are \(n = 200\) offspring, the number of homozygous dominant offspring \(=n\times\frac{1}{2}\)
\(=200\times\frac{1}{2}=100\)

Answer:

100