Question

formula 3 points the effective reproductive number (re) can be defined as the average number of new infections caused by a single infected individual in a partially susceptible population: re = r0*s. if a highly virulent disease has a r0 of 5, but 34 % of the population becomes immune to it, what is the effective reproductive number (re) for this disease? use 1 decimal place only, without units! wrong entries wont be corrected.

Explanation:

Step1: Determine the proportion of susceptible population

The percentage of immune population is 34%, so the proportion of susceptible population ($p$) is $1 - 0.34 = 0.66$.

Step2: Calculate the effective reproductive number ($R_e$)

The formula for $R_e$ is $R_e = R_0 \times p$. Given $R_0 = 5$ and $p = 0.66$, we substitute these values: $R_e = 5 \times 0.66 = 3.3$.

Answer:

3.3