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for every 1 molecule of glucose (c₆h₁₂o₆) and 6 molecules of oxygen gas…

Question

for every 1 molecule of glucose (c₆h₁₂o₆) and 6 molecules of oxygen gas (o₂) that go into cellular respiration, the process produces 6 molecules of carbon dioxide gas (co₂) and 6 molecules of water (h₂o).
complete the table.

Explanation:

Step1: Calculate the number of carbon atoms in 6 molecules of \(CO_2\)

Each \(CO_2\) molecule has 1 carbon atom. So for 6 molecules of \(CO_2\), the number of carbon atoms is \(6\times1 = 6\).

Step2: Calculate the number of oxygen atoms in 6 molecules of \(H_2O\)

Each \(H_2O\) molecule has 1 oxygen atom. So for 6 molecules of \(H_2O\), the number of oxygen atoms is \(6\times1=6\).

Step3: Calculate the total number of hydrogen atoms

The total number of hydrogen atoms is the sum of hydrogen atoms from water (since \(CO_2\) has 0 hydrogen atoms). It is \(12\) (given).

Step4: Calculate the total number of carbon atoms

The total number of carbon atoms is the number of carbon atoms from \(CO_2\) (since \(H_2O\) has 0 carbon atoms). It is \(6\).

Step5: Calculate the total number of oxygen atoms

The total number of oxygen atoms is the sum of oxygen atoms from \(CO_2\) and \(H_2O\). It is \(12 + 6=18\).

Answer:

Type of atomNumber of atoms in 6 molecules of carbon dioxideNumber of atoms in 6 molecules of waterTotal number of atoms in products
C606
O12618