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Question
describing and measuring motion
understanding main ideas
use the following paragraph and graph to answer questions 1 through 5. write your answers on a separate sheet of paper. remember to include units in your answers.
on saturday, ashley rode her bicycle to visit maria. maria’s house is directly east of ashley’s. the graph shows how far ashley was from her house after each minute of her trip.
- ashley rode at a constant speed for the first 4 minutes of her trip. what was her constant speed?
- what was her average speed for the entire trip?
- what was her average velocity for the entire trip?
- ashley stopped to talk with another friend during her trip. how far was she from her house when she stopped?
- ashley’s brother rode beside her for several minutes. during this time, was he moving relative to ashley?
building vocabulary
from the list below, choose the term that best completes each sentence. write your answers on the lines provided.
motion
international system of units
foot
reference point
yard
meter
average
velocity
speed
- scientists around the world use the ____________________, a system of measurement based on the number ten.
- an object is in __________________ when its distance from a(n) __________________ is changing.
- speed in a given direction is ____________________.
- ____________________ can be calculated if you know the distance that an object travels in one unit of time.
- the basic si unit of length is the ____________________.
Question 1
Step1: Identify distance and time
From the graph, at \( t = 4 \) minutes, distance \( d = 800 \) m.
Step2: Use speed formula \( v=\frac{d}{t} \)
\( v=\frac{800\ \text{m}}{4\ \text{min}} = 200\ \text{m/min} \)
Step1: Total distance and time
Total distance \( D = 1600 \) m, total time \( T = 10 \) min.
Step2: Average speed formula \( v_{avg}=\frac{D}{T} \)
\( v_{avg}=\frac{1600\ \text{m}}{10\ \text{min}} = 160\ \text{m/min} \)
Step1: Displacement and time
Displacement is \( 1600 \) m (east), time \( T = 10 \) min.
Step2: Average velocity formula \( v_{avg,vel}=\frac{\text{displacement}}{T} \)
\( v_{avg,vel}=\frac{1600\ \text{m}}{10\ \text{min}} = 160\ \text{m/min (east)} \)
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\( 200\ \text{meters per minute} \)