Question

1. cross a mother and father who are both type \ab.\ what is the probability that they will have a child with type \a\ blood?

Explanation:

Step1: Determine Parental Alleles

Both parents have blood type AB, so their alleles are \( A \) and \( B \) (genotype \( AB \)). Each parent can pass either \( A \) or \( B \) to the child.

Step2: Create Punnett Square

	A	B
B	AB	BB

The possible genotypes are \( AA \), \( AB \), \( AB \), \( BB \).

Step3: Identify Type A Genotype

Type A blood can be \( AA \) (since \( A \) is dominant). From the Punnett square, there's 1 \( AA \) out of 4 total genotypes.

Step4: Calculate Probability

Probability = \( \frac{\text{Number of Type A Genotypes}}{\text{Total Genotypes}} = \frac{1}{4} = 0.25 \) (or 25%).

Answer:

The probability is \( \frac{1}{4} \) (or 25%).