1. construct a model of photosynthesis showing the inputs and outputs (5 pts)
2. construct a model of cellular respiration showing the inputs and outputs (5 pts)
3. bacteria are living in a pond. normally, there is plenty of oxygen available to these bacteria, but an algae bloom has greatly reduced the amount of oxygen in the environment.
a. what type of cellular respiration will the bacteria have to perform? (1 pt)
b. what is the downside of this type of respiration? (1 pt)
use the following data to answer the questions that follow:
effect of differing amounts of water given to a potted plant on glucose production
4. what is the relationship between the amount of water (in ml) and the glucose production (in mg) in the given data? (1 pt)
5. predict the glucose production for a potted plant if it is given 175 ml of water based on the given data. (1 pt)

Question

Accepted Answer

### Question 1: Construct a model of photosynthesis showing the inputs and outputs
# Explanation:
Photosynthesis is the process by which plants, algae, and some bacteria convert light energy into chemical energy (glucose). The inputs are carbon dioxide ($\ce{CO_2}$), water ($\ce{H_2O}$), and light energy. The outputs are glucose ($\ce{C_6H_{12}O_6}$) and oxygen ($\ce{O_2}$). The general equation is: $\ce{6CO_2 + 6H_2O + Light Energy -> C_6H_{12}O_6 + 6O_2}$

So filling in the boxes:
First box (input): $\ce{CO_2}$ (Carbon Dioxide)
Second box (input): $\ce{H_2O}$ (Water)
Third box (input): Light Energy
Fourth box (output): $\ce{C_6H_{12}O_6}$ (Glucose)
Fifth box (output): $\ce{O_2}$ (Oxygen)

### Question 2: Construct a model of cellular respiration showing the inputs and outputs
# Explanation:
Cellular respiration is the process by which cells break down glucose to release energy. The inputs are glucose ($\ce{C_6H_{12}O_6}$) and oxygen ($\ce{O_2}$). The outputs are carbon dioxide ($\ce{CO_2}$), water ($\ce{H_2O}$), and ATP (energy). The general equation is: $\ce{C_6H_{12}O_6 + 6O_2 -> 6CO_2 + 6H_2O + ATP}$

So filling in the boxes:
First box (input): $\ce{C_6H_{12}O_6}$ (Glucose)
Second box (input): $\ce{O_2}$ (Oxygen)
Third box (output): $\ce{CO_2}$ (Carbon Dioxide)
Fourth box (output): $\ce{H_2O}$ (Water)
Fifth box (output): ATP (Adenosine Triphosphate)

### Question 3a: What type of cellular respiration will the bacteria have to perform?
# Brief Explanations:
Normally, bacteria use aerobic respiration (with oxygen). But when oxygen is reduced (due to algae bloom), they switch to anaerobic respiration (fermentation) because anaerobic respiration does not require oxygen.
# Answer:
Anaerobic respiration (or Fermentation)

### Question 3b: What is the downside of this type of respiration?
# Brief Explanations:
Aerobic respiration produces a large amount of ATP (36 - 38 ATP per glucose molecule), while anaerobic respiration (like lactic acid fermentation or alcoholic fermentation) produces much less ATP (only 2 ATP per glucose molecule). Also, anaerobic respiration can produce toxic by - products (e.g., lactic acid or ethanol) which can be harmful to the cell if they accumulate.
# Answer:
Produces much less ATP (energy) than aerobic respiration, and may produce toxic by - products (e.g., lactic acid, ethanol)

### Question 4: What is the relationship between the amount of water (in ml) and the glucose production (in mg) in the given data?
# Explanation:
Let's check the ratio of glucose production to water amount for each data point:
- For 50 ml water: $\frac{12\space mg}{50\space ml}= 0.24\space mg/ml$
- For 100 ml water: $\frac{24\space mg}{100\space ml}=0.24\space mg/ml$
- For 150 ml water: $\frac{36\space mg}{150\space ml}=0.24\space mg/ml$
- For 200 ml water: $\frac{48\space mg}{200\space ml}=0.24\space mg/ml$
- For 250 ml water: $\frac{60\space mg}{250\space ml}=0.24\space mg/ml$

Since the ratio of glucose production to water amount is constant (0.24 mg/ml), the relationship is a direct proportional relationship. As the amount of water (in ml) increases, the glucose production (in mg) increases proportionally.
# Answer:
There is a direct proportional relationship. As the amount of water (in ml) increases, the glucose production (in mg) increases proportionally (the ratio of glucose production to water amount is constant at 0.24 mg/ml).

### Question 5: Predict the glucose production for a potted plant if it is given 175 ml of water based on the given data.
# Explanation:
From the data, we know that the ratio of glucose production ($y$) to water amount ($x$) is $y = 0.24x$ (since $\frac{y}{x}=0.24$ from the previous calculation).

We are given $x = 175\space ml$. To find $y$ (glucose production), we use the formula $y=0.24	imes x$

## Step 1: Identify the relationship
We have determined that $y = 0.24x$, where $y$ is glucose production in mg and $x$ is water amount in ml.

## Step 2: Substitute the value of $x$
Substitute $x = 175$ into the equation: $y=0.24	imes175$

## Step 3: Calculate the result
$0.24	imes175 = 42$

# Answer:
42 mg

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QUESTION IMAGE

Question

Explanation:

Question 1: Construct a model of photosynthesis showing the inputs and outputs

Question 2: Construct a model of cellular respiration showing the inputs and outputs

Question 3a: What type of cellular respiration will the bacteria have to perform?

Answer:

Question 3b: What is the downside of this type of respiration?