Question

clyde has the recessive, no tongue (tt) trait. amelia has a heterozygous genotype for her tongue (tt).
clyde
amelia
phenotype probability (%)
tongue:
no tongue:

Explanation:

Step1: Determine Gametes

Clyde's genotype is \( tt \), so he can only produce \( t \) gametes. Amelia's genotype is \( Tt \), so she can produce \( T \) and \( t \) gametes.

Step2: Complete Punnett Square

	\( t \)	\( t \)
\( t \)	\( tt \)	\( tt \)

Step3: Calculate Phenotype Probabilities

• For "Tongue" (genotype \( Tt \)): There are 2 out of 4 squares, so probability is \( \frac{2}{4} \times 100\% = 50\% \).
• For "No tongue" (genotype \( tt \)): There are 2 out of 4 squares, so probability is \( \frac{2}{4} \times 100\% = 50\% \).

Answer:

Tongue: \( 50\% \)
No tongue: \( 50\% \)