Question

1. a black chicken and a white chicken are crossed. what is the probability that they will have erminette chicks? 50% parents: b x w show the punnett square:

Explanation:

Step1: Set up alleles

Let \(B\) represent the allele for black and \(W\) represent the allele for white. In incomplete - dominance, erminette is the heterozygous phenotype (\(BW\)).

Step2: Create Punnett - square

	B
W	BW

The possible genotypes of the offspring are all \(BW\).

Answer:

100%