Question

the allele for curly hair is (c) and the allele for straight hair is (c). when two heterozygotes are crossed, what percentage of the offspring is expected to be homozygous for smooth hair?
100%
25%
100%
0%

Explanation:

Step1: Determine the genotypes of the parents

The allele for curly hair is \(C\) and for straight hair is \(c\). The parents are heterozygous, so their genotypes are \(Cc\).

Step2: Create a Punnett square

	\(C\)	\(c\)
\(c\)	\(Cc\)	\(cc\)

Step3: Calculate the percentage of homozygous for smooth hair (\(cc\))

From the Punnett square, there are 4 possible offspring genotypes. The genotype \(cc\) (smooth hair) appears 1 time. So the percentage is \(\frac{1}{4}\times100\% = 25\%\)

Answer:

25%