activity b (continued from previous page)
7. summarize: based on what you have seen, write a simplified formula for cellular respiration.
______ + ______ → ______ + ______
turn on show input/output formula to check. were you correct? ________
6. challenge: to balance the inputs and outputs of cellular respiration, there should be the same number of carbon, oxygen, and hydrogen atoms on each side of the arrow.
a. is the formula balanced as written? why or why not? ________________________
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b. now balance the input/output formula by adding coefficients to each molecule. write the balanced formula below, and then check your work by clicking balance.
____ ______ + ____ ______ → ____ ______ + ____ ______
8. compare: the aerobic phase of cellular respiration in the mitochondrion produces a net of about 28 to 30 atp molecules. how does this compare to the energy released in glycolysis?
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(note: some textbooks state that up to 36 atp molecules are produced in this phase of cellular respiration. in reality, some energy is lost in the process due to the cost of transporting molecules and imperfect membranes.)
9. extend your thinking: when you think of the word
espiration,\ you might think about the process of breathing, which is actually called ventilation. (the respiratory system consists of the windpipe, lungs, etc.)
how is breathing related to cellular respiration? (hint: think about both the inputs and the outputs of cellular respiration.)
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Accepted Answer

# Brief Explanations:
Cellular respiration is a biological process. The simplified formula for cellular respiration (before balancing) is glucose ($C_6H_{12}O_6$) and oxygen ($O_2$) as inputs, and carbon dioxide ($CO_2$) and water ($H_2O$) as outputs. Glycolysis produces a net of 2 ATP molecules, while the aerobic phase (in mitochondria) produces much more (28 - 30 ATP). Breathing (ventilation) supplies oxygen (an input for cellular respiration) and removes carbon dioxide (an output of cellular respiration).

# Answer:
7. $C_6H_{12}O_6+O_2
ightarrow CO_2 + H_2O$ (This is the un - balanced formula. After checking with the simulation, if it's a basic formula without coefficients, this is a start. But usually, the balanced formula is $C_6H_{12}O_6 + 6O_2
ightarrow6CO_2+6H_2O$).
6. A. No. For example, in the un - balanced formula $C_6H_{12}O_6+O_2
ightarrow CO_2 + H_2O$, the number of carbon atoms: 6 on the left (in $C_6H_{12}O_6$) and 1 on the right (in $CO_2$); hydrogen atoms: 12 on the left (in $C_6H_{12}O_6$) and 2 on the right (in $H_2O$); oxygen atoms: $6 + 2=8$ on the left ($6$ in $C_6H_{12}O_6$ and $2$ in $O_2$) and $2 + 1=3$ on the right ($2$ in $CO_2$ and $1$ in $H_2O$).
B. $1C_6H_{12}O_6+6O_2
ightarrow6CO_2 + 6H_2O$
8. The aerobic phase of cellular respiration (in mitochondria) produces much more ATP. Glycolysis produces a net of 2 ATP, while the aerobic phase produces 28 - 30 ATP (a 14 - 15 times increase approximately).
9. Breathing (ventilation) brings in oxygen ($O_2$), which is an input for cellular respiration. It also removes carbon dioxide ($CO_2$), which is an output of cellular respiration.

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