Question

15 multiple choice 1 point if 25% of the population shows a recessive trait, what percent is expected to be homozygous dominant? 50% 25% 36% 56.25%

Explanation:

Step1: Use Hardy - Weinberg equation

The Hardy - Weinberg equation is \(p^{2}+2pq + q^{2}=1\), where \(q^{2}\) is the frequency of homozygous recessive individuals. Given that \(q^{2}=0.25\) (since 25% = 0.25).

Step2: Find \(q\)

Take the square root of \(q^{2}\). So, \(q=\sqrt{0.25}=0.5\)

Step3: Find \(p\)

Since \(p + q=1\), then \(p=1 - q\). Substituting \(q = 0.5\), we get \(p=1 - 0.5=0.5\)

Step4: Find \(p^{2}\)

\(p^{2}\) is the frequency of homozygous dominant individuals. So, \(p^{2}=(0.5)^{2}=0.25\) (25%)

Answer:

25%