question 5 1 pts which of the following equations is not balanced? $c_{3}h_{8}+5o_{2}\to3co_{2}+4h_{2}o$ $so_{2}+o_{2}\to so_{3}$ $2h_{2}+o_{2}\to2h_{2}o$ $2na + 2h_{2}o\to2naoh + h_{2}$ $2al+6hcl\to2alcl_{3}+3h_{2}$ question 6 1 pts when the following reaction is balanced the coefficient in front of carbon dioxide is: $c_{5}h_{12}(l)+o_{2}(g)\to co_{2}(g)+h_{2}o(g)$ 5 12 6 10

Question

Accepted Answer

### Question 5
# Explanation:
## Step1: Check $C_3H_8 + 5O_2
ightarrow3CO_2 + 4H_2O$
- **Carbon ($C$)**: Left side has $3$ atoms ($C_3H_8$), right side has $3$ atoms ($3CO_2$).
- **Hydrogen ($H$)**: Left side has $8$ atoms ($C_3H_8$), right side has $8$ atoms ($4H_2O$).
- **Oxygen ($O$)**: Left side has $10$ atoms ($5O_2$), right side has $3\times2 + 4\times1=10$ atoms ($3CO_2+4H_2O$).
## Step2: Check $SO_2 + O_2
ightarrow SO_3$
- **Sulfur ($S$)**: Left side has $1$ atom ($SO_2$), right side has $1$ atom ($SO_3$).
- **Oxygen ($O$)**: Left side has $2 + 2=4$ atoms ($SO_2+O_2$), right side has $3$ atoms ($SO_3$).
## Step3: Check $2H_2+O_2
ightarrow2H_2O$
- **Hydrogen ($H$)**: Left side has $4$ atoms ($2H_2$), right side has $4$ atoms ($2H_2O$).
- **Oxygen ($O$)**: Left side has $2$ atoms ($O_2$), right side has $2$ atoms ($2H_2O$).
## Step4: Check $2Na + 2H_2O
ightarrow2NaOH+H_2$
- **Sodium ($Na$)**: Left side has $2$ atoms ($2Na$), right side has $2$ atoms ($2NaOH$).
- **Hydrogen ($H$)**: Left side has $4$ atoms ($2H_2O$), right side has $2 + 2=4$ atoms ($2NaOH + H_2$).
- **Oxygen ($O$)**: Left side has $2$ atoms ($2H_2O$), right side has $2$ atoms ($2NaOH$).
## Step5: Check $2Al+6HCl
ightarrow2AlCl_3 + 3H_2$
- **Aluminum ($Al$)**: Left side has $2$ atoms ($2Al$), right side has $2$ atoms ($2AlCl_3$).
- **Hydrogen ($H$)**: Left side has $6$ atoms ($6HCl$), right side has $6$ atoms ($3H_2$).
- **Chlorine ($Cl$)**: Left side has $6$ atoms ($6HCl$), right side has $6$ atoms ($2AlCl_3$).

# Answer:
$SO_2 + O_2
ightarrow SO_3$

### Question 6
# Explanation:
## Step1: Balance carbon ($C$)
- For $C_5H_{12}(l)+O_2(g)
ightarrow CO_2(g)+H_2O(g)$, first balance $C$. Since there are $5$ $C$ atoms in $C_5H_{12}$, we put a coefficient of $5$ in front of $CO_2$. The equation becomes $C_5H_{12}(l)+O_2(g)
ightarrow5CO_2(g)+H_2O(g)$.
## Step2: Balance hydrogen ($H$)
- There are $12$ $H$ atoms in $C_5H_{12}$. So we put a coefficient of $6$ in front of $H_2O$ (because $6\times2 = 12$). The equation is $C_5H_{12}(l)+O_2(g)
ightarrow5CO_2(g)+6H_2O(g)$.
## Step3: Balance oxygen ($O$)
- On the right - hand side, the number of $O$ atoms is $5\times2+6\times1=16$. So we put a coefficient of $8$ in front of $O_2$ (since $8\times2 = 16$). The balanced equation is $C_5H_{12}(l)+8O_2(g)
ightarrow5CO_2(g)+6H_2O(g)$.

# Answer:
$5$

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QUESTION IMAGE

Question

Explanation:

Question 5

Step1: Check \(C_3H_8 + 5O_2

Step2: Check \(SO_2 + O_2

Step3: Check \(2H_2+O_2

Step4: Check \(2Na + 2H_2O

Step5: Check \(2Al+6HCl

Step1: Balance carbon (\(C\))

Step2: Balance hydrogen (\(H\))

Step3: Balance oxygen (\(O\))

Answer:

Question 6