Question

question 10 (2 points)
state whether this is an ionic or covalent compound and then explain how you would determine the formula:
ammonium nitrate

question 11 (2 points)
state whether this compound is ionic or covalent and then explain how you would determine the name:
\\(\text{nh}_4\text{br}\\)

Explanation:

Classify ammonium nitrate and derive its formula

Using the Ionic Bonding and Polyatomic Ion Compounds knowledge points

• Ammonium nitrate consists of polyatomic ions: ammonium \(\text{NH}_4^+\) and nitrate \(\text{NO}_3^-\).
• Since it is composed of oppositely charged ions, it is an ionic compound.
• Using the Chemical Formula Derivation knowledge point, we balance the charges:

$$ (+1) + (-1) = 0 $$

• The balanced chemical formula is \(\text{NH}_4\text{NO}_3\).

Classify NH4Br and explain its nomenclature

Using the Chemical Nomenclature and Ionic Bonding knowledge points

• \(\text{NH}_4\text{Br}\) consists of the ammonium cation \(\text{NH}_4^+\) and the bromide anion \(\text{Br}^-\).
• Because it is held together by electrostatic attraction between ions, it is an ionic compound.
• To name it, state the cation name first, followed by the anion name with the "-ide" suffix:

$$ \text{ammonium} + \text{bromide} = \text{ammonium bromide} $$

Answer:

Question 10

• Classification: Ionic compound
• Explanation: Ammonium nitrate is composed of two polyatomic ions: the ammonium cation (\(\text{NH}_4^+\)) and the nitrate anion (\(\text{NO}_3^-\)). Because it is made of ions, it is an ionic compound. To determine the formula, balance the \(+1\) charge of ammonium with the \(-1\) charge of nitrate in a 1:1 ratio, yielding \(\text{NH}_4\text{NO}_3\).

Question 11

• Classification: Ionic compound
• Explanation: \(\text{NH}_4\text{Br}\) is composed of the polyatomic ammonium cation (\(\text{NH}_4^+\)) and the monatomic bromide anion (\(\text{Br}^-\)), making it an ionic compound. To determine the name, identify the positive ion as "ammonium" and the negative halogen ion as "bromide" (from bromine, changing the ending to "-ide"), combining them to get "ammonium bromide".