QUESTION IMAGE
Question
question 10 (2 points)
state whether this is an ionic or covalent compound and then explain how you would determine the formula:
ammonium nitrate
question 11 (2 points)
state whether this compound is ionic or covalent and then explain how you would determine the name:
\\(\text{nh}_4\text{br}\\)
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</pre_analysis>
<reasoning>
Classify ammonium nitrate and derive its formula
Using the Ionic Bonding and Polyatomic Ion Compounds knowledge points
- Ammonium nitrate consists of polyatomic ions: ammonium \(\text{NH}_4^+\) and nitrate \(\text{NO}_3^-\).
- Since it is composed of oppositely charged ions, it is an ionic compound.
- Using the Chemical Formula Derivation knowledge point, we balance the charges:
\[
(+1) + (-1) = 0
\]
- The balanced chemical formula is \(\text{NH}_4\text{NO}_3\).
Classify NH4Br and explain its nomenclature
Using the Chemical Nomenclature and Ionic Bonding knowledge points
- \(\text{NH}_4\text{Br}\) consists of the ammonium cation \(\text{NH}_4^+\) and the bromide anion \(\text{Br}^-\).
- Because it is held together by electrostatic attraction between ions, it is an ionic compound.
- To name it, state the cation name first, followed by the anion name with the "-ide" suffix:
\[
\text{ammonium} + \text{bromide} = \text{ammonium bromide}
\]
</reasoning>
<answer>
Question 10
- Classification: Ionic compound
- Explanation: Ammonium nitrate is composed of two polyatomic ions: the ammonium cation (\(\text{NH}_4^+\)) and the nitrate anion (\(\text{NO}_3^-\)). Because it is made of ions, it is an ionic compound. To determine the formula, balance the \(+1\) charge of ammonium with the \(-1\) charge of nitrate in a 1:1 ratio, yielding \(\text{NH}_4\text{NO}_3\).
Question 11
- Classification: Ionic compound
- Explanation: \(\text{NH}_4\text{Br}\) is composed of the polyatomic ammonium cation (\(\text{NH}_4^+\)) and the monatomic bromide anion (\(\text{Br}^-\)), making it an ionic compound. To determine the name, identify the positive ion as "ammonium" and the negative halogen ion as "bromide" (from bromine, changing the ending to "-ide"), combining them to get "ammonium bromide".
</answer>
<post_analysis>
{
"subject": "Natural Science",
"question_type": "Multi-part",
"knowledge_point": [
"Natural Science",
"Chemistry",
"Chemical Nomenclature"
]
}
</post_analysis>
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<pre_analysis>
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"needs_drawing": false,
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"Chemical Nomenclature",
"Ionic Bonding",
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"new_concepts": [],
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"Chemical Nomenclature",
"Ionic Bonding",
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</pre_analysis>
<reasoning>
Classify ammonium nitrate and derive its formula
Using the Ionic Bonding and Polyatomic Ion Compounds knowledge points
- Ammonium nitrate consists of polyatomic ions: ammonium \(\text{NH}_4^+\) and nitrate \(\text{NO}_3^-\).
- Since it is composed of oppositely charged ions, it is an ionic compound.
- Using the Chemical Formula Derivation knowledge point, we balance the charges:
\[
(+1) + (-1) = 0
\]
- The balanced chemical formula is \(\text{NH}_4\text{NO}_3\).
Classify NH4Br and explain its nomenclature
Using the Chemical Nomenclature and Ionic Bonding knowledge points
- \(\text{NH}_4\text{Br}\) consists of the ammonium cation \(\text{NH}_4^+\) and the bromide anion \(\text{Br}^-\).
- Because it is held together by electrostatic attraction between ions, it is an ionic compound.
- To name it, state the cation name first, followed by the anion name with the "-ide" suffix:
\[
\text{ammonium} + \text{bromide} = \text{ammonium bromide}
\]
</reasoning>
<answer>
Question 10
- Classification: Ionic compound
- Explanation: Ammonium nitrate is composed of two polyatomic ions: the ammonium cation (\(\text{NH}_4^+\)) and the nitrate anion (\(\text{NO}_3^-\)). Because it is made of ions, it is an ionic compound. To determine the formula, balance the \(+1\) charge of ammonium with the \(-1\) charge of nitrate in a 1:1 ratio, yielding \(\text{NH}_4\text{NO}_3\).
Question 11
- Classification: Ionic compound
- Explanation: \(\text{NH}_4\text{Br}\) is composed of the polyatomic ammonium cation (\(\text{NH}_4^+\)) and the monatomic bromide anion (\(\text{Br}^-\)), making it an ionic compound. To determine the name, identify the positive ion as "ammonium" and the negative halogen ion as "bromide" (from bromine, changing the ending to "-ide"), combining them to get "ammonium bromide".
</answer>
<post_analysis>
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"knowledge_point": [
"Natural Science",
"Chemistry",
"Chemical Nomenclature"
]
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</post_analysis>