QUESTION IMAGE
Question
- __licl + br₂ → libr + __cl₂
Step1: Balance chlorine and bromine atoms
We have \(Cl\) in \(LiCl\) and \(Cl_2\), and \(Br\) in \(Br_2\) and \(LiBr\). Let's first balance the halogen (group 17 elements) atoms.
For bromine: There are \(2\) \(Br\) atoms in \(Br_2\). So we need \(2\) \(LiBr\) to balance \(Br\) atoms.
For chlorine: If we have \(2\) \(LiBr\), then for \(Li\) balance (since \(Li\) is in \(LiCl\) and \(LiBr\)), we need \(2\) \(LiCl\). And \(2\) \(LiCl\) will give \(2\) \(Cl\) atoms, which is balanced with \(Cl_2\) (since \(Cl_2\) has \(2\) \(Cl\) atoms).
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
\(2\) \(LiCl+1\) \(Br_2\to2\) \(LiBr + 1\) \(Cl_2\)