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4) ____licl + ____br₂ → ____libr + ____cl₂

Question

  1. __licl + br₂ → libr + __cl₂

Explanation:

Step1: Balance chlorine and bromine atoms

We have \(Cl\) in \(LiCl\) and \(Cl_2\), and \(Br\) in \(Br_2\) and \(LiBr\). Let's first balance the halogen (group 17 elements) atoms.
For bromine: There are \(2\) \(Br\) atoms in \(Br_2\). So we need \(2\) \(LiBr\) to balance \(Br\) atoms.
For chlorine: If we have \(2\) \(LiBr\), then for \(Li\) balance (since \(Li\) is in \(LiCl\) and \(LiBr\)), we need \(2\) \(LiCl\). And \(2\) \(LiCl\) will give \(2\) \(Cl\) atoms, which is balanced with \(Cl_2\) (since \(Cl_2\) has \(2\) \(Cl\) atoms).

Answer:

\(2\) \(LiCl+1\) \(Br_2\to2\) \(LiBr + 1\) \(Cl_2\)