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which solution is valid within the context of the situation? (200.5, 50…

Question

which solution is valid within the context of the situation?

(200.5, 50)
(180, 80)
(300, -40)
(100, 100)

Explanation:

Response

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<reasoning>

Identify the feasible region

We analyze the shaded region representing the Systems of Linear Inequalities.
The overlapping shaded region (feasible region) is the darker band.
It lies entirely in the first quadrant where \(x \ge 0\) and \(y \ge 0\).
This represents standard Real-world Constraints where quantities must be non-negative.

Determine boundary lines

We estimate the boundary lines from the Graphical Solutions.
The first boundary line passes through approximately \((250, 0)\) and \((0, 250)\).
The second boundary line passes through approximately \((300, 0)\) and \((0, 300)\).
The feasible region is the band between these two lines:
\[250 \le x + y \le 300\]
with non-negativity constraints \(x \ge 0, y \ge 0\).

Test the given options

We evaluate each option using Feasible Region Interpretation:

  • For \((200.5, 50)\): \(x + y = 200.5 + 50 = 250.5\). This lies within the band, but real-world contexts often require integer values. Let's check other options.
  • For \((180, 80)\): \(x + y = 180 + 80 = 260\). This is a pair of positive integers lying well inside the region.
  • For \((300, -40)\): \(y = -40 < 0\), violating the non-negativity constraint.
  • For \((100, 100)\): \(x + y = 200 < 250\), which lies outside the shaded band.

Select the valid solution

Comparing the remaining candidates, \((180, 80)\) consists of whole numbers.
It lies strictly inside the shaded region.
Thus, \((180, 80)\) is the most valid solution.
</reasoning>

<answer>
<mcq-option>(A) (200.5,50)</mcq-option>
<mcq-correct>(B) (180,80)</mcq-correct>
<mcq-option>(C) (300,-40)</mcq-option>
<mcq-option>(D) (100,100)</mcq-option>
</answer>

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"Mathematics",
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"Systems of Linear Inequalities"
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</post_analysis>

Answer:

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<reasoning>

Identify the feasible region

We analyze the shaded region representing the Systems of Linear Inequalities.
The overlapping shaded region (feasible region) is the darker band.
It lies entirely in the first quadrant where \(x \ge 0\) and \(y \ge 0\).
This represents standard Real-world Constraints where quantities must be non-negative.

Determine boundary lines

We estimate the boundary lines from the Graphical Solutions.
The first boundary line passes through approximately \((250, 0)\) and \((0, 250)\).
The second boundary line passes through approximately \((300, 0)\) and \((0, 300)\).
The feasible region is the band between these two lines:
\[250 \le x + y \le 300\]
with non-negativity constraints \(x \ge 0, y \ge 0\).

Test the given options

We evaluate each option using Feasible Region Interpretation:

  • For \((200.5, 50)\): \(x + y = 200.5 + 50 = 250.5\). This lies within the band, but real-world contexts often require integer values. Let's check other options.
  • For \((180, 80)\): \(x + y = 180 + 80 = 260\). This is a pair of positive integers lying well inside the region.
  • For \((300, -40)\): \(y = -40 < 0\), violating the non-negativity constraint.
  • For \((100, 100)\): \(x + y = 200 < 250\), which lies outside the shaded band.

Select the valid solution

Comparing the remaining candidates, \((180, 80)\) consists of whole numbers.
It lies strictly inside the shaded region.
Thus, \((180, 80)\) is the most valid solution.
</reasoning>

<answer>
<mcq-option>(A) (200.5,50)</mcq-option>
<mcq-correct>(B) (180,80)</mcq-correct>
<mcq-option>(C) (300,-40)</mcq-option>
<mcq-option>(D) (100,100)</mcq-option>
</answer>

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