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Question
find the slope of the line joining two points \\((4, -2)\\) and \\((6, -8)\\).
\\(\bigcirc\\) \\(1/3\\)
\\(\bigcirc\\) \\(-3\\)
Identify the coordinates of the given points
$$
(x_1, y_1) = (4, -2),\quad (x_2, y_2) = (6, -8)
$$
Apply the slope formula
$$
m = \frac{y_2 - y_1}{x_2 - x_1}
$$
Calculate the value of the slope
$$
m = \frac{-8 - (-2)}{6 - 4} = \frac{-8 + 2}{2} = \frac{-6}{2} = -3
$$
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- (A) \(1/3\)
- (B) \(-3\) (Correct answer)