Question

find the slope of the line joining two points \\((4, -2)\\) and \\((6, -8)\\).

\\(\bigcirc\\) \\(1/3\\)

\\(\bigcirc\\) \\(-3\\)

Explanation:

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<reasoning>

Identify the coordinates of the given points

\[
(x_1, y_1) = (4, -2),\quad (x_2, y_2) = (6, -8)
\]

Apply the slope formula

\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]

Calculate the value of the slope

\[
m = \frac{-8 - (-2)}{6 - 4} = \frac{-8 + 2}{2} = \frac{-6}{2} = -3
\]
</reasoning>

<answer>
<mcq-option>(A) \(1/3\)</mcq-option>
<mcq-correct>(B) \(-3\)</mcq-correct>
</answer>

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Answer:

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<reasoning>

Identify the coordinates of the given points

\[
(x_1, y_1) = (4, -2),\quad (x_2, y_2) = (6, -8)
\]

Apply the slope formula

\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]

Calculate the value of the slope

\[
m = \frac{-8 - (-2)}{6 - 4} = \frac{-8 + 2}{2} = \frac{-6}{2} = -3
\]
</reasoning>

<answer>
<mcq-option>(A) \(1/3\)</mcq-option>
<mcq-correct>(B) \(-3\)</mcq-correct>
</answer>

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