Question

1. the wind pushing the sailboat has an acceleration force of 250n. the boat feels an 80n force of friction. the sailboat has a mass of about 1100kg. using this information, the acceleration of the boat is...

a. 0.15 m/s²
b. 6.47 m/s²
c. 0.30 m/s²
d. 0.23 m/s²

1. what is the net force of acting on the box shown to the right?

a. unbalanced, zero net force
b. balanced, zero net force
c. unbalanced, non - zero net force
d. balanced, non - zero net force

1. which statement best describes the motion of the box shown to the right?

a. it is not moving.
b. it is positively accelerating to the right.
c. it is negatively accelerating to the right.
d. it is moving at a constant speed to the right.

1. which statement best describes the relationship of an objects mass and acceleration?

a. there is no relationship between an objects mass and acceleration.
b. the heavier the object, the greater its acceleration.
c. the relationship between an objects mass and acceleration cannot be determined.
d. the lighter the object, the greater its acceleration.

1. what is true about the forces and the motion on the box above?

a. the forces are balanced and the box will accelerate to the left
b. the forces are unbalanced and the box will accelerate to the right
c. the forces are unbalanced and the box will accelerate to the left
d. the forces are unbalanced and the box will move at a constant speed to the right

1. what is the net force on the box shown above?

a. 10 n to the left
b. 10 n to the right
c. 20 n to the right
d. 0 n

1. what is the force that a bodybuilder exerts to push 150 kg weights at an acceleration of 3m/s2?

a. 153 n
b. 0.02 n
c. 50 n
d. 450 n

Explanation:

Step1: Calcular la fuerza neta

La fuerza neta \( F_{net} \) se calcula restando la fuerza de fricción \( F_{friction} \) de la fuerza de aceleración \( F_{acceleration} \).
\( F_{net}=F_{acceleration}-F_{friction} \)
Sustituyendo los valores: \( F_{net}=250N - 80N=170N \)

Step2: Aplicar la segunda ley de Newton

La segunda ley de Newton es \( F = ma \), donde \( F \) es la fuerza neta, \( m \) es la masa y \( a \) es la aceleración. Despejando \( a \) se obtiene \( a=\frac{F}{m} \)
Sustituyendo \( F = 170N \) y \( m = 1100kg \):
\( a=\frac{170}{1100}\approx0.15m/s^{2} \)

Answer:

A. \( 0.15 m/s^{2} \)