Question

1. the wind pushing the sailboat has an acceleration force of 250n. the boat feels an 80n force of friction. the sailboat has a mass of about 1100kg. using this information, the acceleration of the boat is...

a. 0.15 m/s²
b. 6.47 m/s²
c. 0.30 m/s²
d. 0.23 m/s²

1. what is the net force of acting on the box shown to the right?

a. unbalanced, zero net force
b. balanced, zero net force
c. unbalanced, non - zero net force
d. balanced, non - zero net force

1. which statement best describes the motion of the box shown to the right?

a. it is not moving.
b. it is positively accelerating to the right.
c. it is negatively accelerating to the right.
d. it is moving at a constant speed to the right.

1. which statement best describes the relationship of an objects mass and acceleration?

a. there is no relationship between an objects mass and acceleration.
b. the heavier the object, the greater its acceleration.
c. the relationship between an objects mass and acceleration cannot be determined.
d. the lighter the object, the greater its acceleration.

Explanation:

Step1: Aplicar la segunda ley de Newton

La segunda ley de Newton establece que \(F_{net}=ma\), donde \(F_{net}\) es la fuerza neta, \(m\) es la masa y \(a\) es la aceleración.

Step2: Calcular la fuerza neta

La fuerza neta es \(F_{net}=F_{aplicada}-F_{fricción}\). Dado que \(F_{aplicada} = 250N\) y \(F_{fricción}=80N\), entonces \(F_{net}=250 - 80=170N\).

Step3: Despejar la aceleración

De \(F_{net}=ma\), despejamos \(a=\frac{F_{net}}{m}\). Sustituyendo \(F_{net} = 170N\) y \(m = 1100kg\), tenemos \(a=\frac{170}{1100}\approx0.1545m/s^{2}\approx0.15m/s^{2}\)

Answer:

A. \(0.15m/s^{2}\)