Question

a winch performs 4,500 j of work to lift a load in 15 s. the average power output of the winch is ________.

Explanation:

Step1: Recall the formula for power

Power \( P=\frac{W}{t} \), where \( W \) is work and \( t \) is time.

Step2: Substitute the given values

Given \( W = 4500\space J \) and \( t=15\space s \). Then \( P=\frac{4500}{15} \).

Step3: Calculate the value

\( \frac{4500}{15}=300\space W \)

Answer:

\( 300\space W \)