QUESTION IMAGE
Question
- willie robertson shoots horizontally at a duck from a height of 6m. if the initial velocity of the bullet is 95 m/s.
picture:
a. find the time it takes for the bullet to hit the ground.
formula:
plug in numbers:
answer:
b. find the horizontal distance traveled during that time... assuming he missed the duck.
formula:
plug in numbers:
answer:
c. what is the final vertical velocity?
formula:
plug in numbers:
answer:
a. Find the time it takes for the bullet to hit the ground
Step1: 垂直方向運動公式
垂直方向初速度\(v_{0y}=0\),根據自由落體位移公式\(y = v_{0y}t+\frac{1}{2}gt^{2}\),可化為\(y=\frac{1}{2}gt^{2}\)(\(y = 6m\),\(g = 9.8m/s^{2}\))。
Step2: 求解時間\(t\)
由\(y=\frac{1}{2}gt^{2}\),可得\(t=\sqrt{\frac{2y}{g}}\),代入\(y = 6m\),\(g = 9.8m/s^{2}\),\(t=\sqrt{\frac{2\times6}{9.8}}\approx1.11s\)。
Step1: 水平方向運動公式
水平方向做勻速直線運動,公式\(x = v_{0x}t\)(\(v_{0x}=95m/s\),\(t\approx1.11s\))。
Step2: 計算水平距離\(x\)
代入數值\(x = 95\times1.11 = 105.45m\)。
Step1: 垂直方向速度公式
根據\(v_{y}=v_{0y}+gt\)(\(v_{0y}=0\),\(g = 9.8m/s^{2}\),\(t\approx1.11s\))。
Step2: 計算最終垂直速度\(v_{y}\)
代入得\(v_{y}=0 + 9.8\times1.11=10.88m/s\)。
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\(t\approx1.11s\)