Question

in which scenario is the greatest amount of work done on a wagon? a force of 55 n moves it 8 m. a force of 60 n moves it 6 m. a force of 50 n moves it 5 m. a force of 40 n moves it 10 m.

Explanation:

1. Recall the work - formula:

• The work done \(W\) by a constant force \(F\) over a displacement \(d\) is given by \(W = F\times d\) (when the force and displacement are in the same direction).

1. Calculate the work done for each scenario:

• For the first scenario: \(F = 55\ N\) and \(d = 8\ m\), so \(W_1=F\times d=55\times8 = 440\ J\).
• For the second scenario: \(F = 60\ N\) and \(d = 6\ m\), so \(W_2=F\times d=60\times6=360\ J\).
• For the third scenario: \(F = 50\ N\) and \(d = 5\ m\), so \(W_3=F\times d=50\times5 = 250\ J\).
• For the fourth scenario: \(F = 40\ N\) and \(d = 10\ m\), so \(W_4=F\times d=40\times10 = 400\ J\).

1. Compare the work - values:

• Since \(440>400 > 360>250\), the greatest amount of work is done in the scenario where a force of \(55\ N\) moves the wagon \(8\ m\).

Answer:

A force of 55 N moves it 8 m.