Question

what is the rate of acceleration of a 2,000 kg truck if a force of 4,200 n is used to make it start moving forward?

Explanation:

Step1: Recall Newton's second law

Newton's second law is \(F = ma\), where \(F\) is force, \(m\) is mass, and \(a\) is acceleration. We need to solve for \(a\), so we can rewrite the formula as \(a=\frac{F}{m}\).

Step2: Substitute the given values

Given \(F = 4200\space N\) and \(m = 2000\space kg\). Substitute these into the formula \(a=\frac{4200}{2000}\).

Step3: Calculate the acceleration

\(a=\frac{4200}{2000}= 2.1\space m/s^{2}\)

Answer:

\(2.1\space m/s^{2}\)