Question

what is the quantity of work done when a crane lifts a 100-n block from 2 m above the ground to 6 m above the ground?

○ 100 j

○ 200 j

○ 400 j

○ 600 j

Explanation:

Step1: Recall Work Formula

Work \( W \) is calculated as \( W = F \times d \), where \( F \) is force and \( d \) is displacement in the direction of force.

Step2: Determine Displacement

The block moves from \( 2 \, \text{m} \) to \( 6 \, \text{m} \), so displacement \( d = 6 - 2 = 4 \, \text{m} \).

Step3: Calculate Work

Force \( F = 100 \, \text{N} \), displacement \( d = 4 \, \text{m} \). Using \( W = F \times d \), we get \( W = 100 \times 4 = 400 \, \text{J} \).

Answer:

400 J