Question

what is the missing particle?
? \to \begin{array}{r} 0 \\ -1 end{array} e+\begin{array}{r} 34 \\ 16 end{array} s
\begin{array}{r} 34 \\ 15 end{array} p quad \begin{array}{r} 34 \\ 15 end{array} s quad \begin{array}{r} 34 \\ 16 end{array} p

Explanation:

Step1: Balance atomic number

The atomic number of the product side is \(-1 + 16=15\).

Step2: Balance mass number

The mass number of the product side is \(0 + 34 = 34\).

Step3: Identify the element

The element with atomic number \(15\) is phosphorus (\(P\)).

Answer:

\(\ce{^{34}_{15}P}\)